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N Queen Problem
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Backtracking/N Queens.cpp
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82
Backtracking/N Queens.cpp
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#include<iostream>
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#define N 4
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using namespace std;
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void printSolution(int board[N][N])
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{
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cout<<"\n";
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for (int i = 0; i < N; i++)
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{
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for (int j = 0; j < N; j++)
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cout<<""<<board[i][j];
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cout<<"\n";
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}
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}
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bool isSafe(int board[N][N], int row, int col)
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{
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int i, j;
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/* Check this row on left side */
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for (i = 0; i < col; i++)
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if (board[row][i])
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return false;
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/* Check upper diagonal on left side */
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for (i=row, j=col; i>=0 && j>=0; i--, j--)
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if (board[i][j])
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return false;
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/* Check lower diagonal on left side */
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for (i=row, j=col; j>=0 && i<N; i++, j--)
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if (board[i][j])
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return false;
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return true;
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}
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void solveNQ(int board[N][N], int col)
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{
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if (col >= N){
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printSolution(board);
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return;
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}
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/* Consider this column and try placing
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this queen in all rows one by one */
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for (int i = 0; i < N; i++)
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{
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/* Check if queen can be placed on
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board[i][col] */
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if ( isSafe(board, i, col) )
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{
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/* Place this queen in board[i][col] */
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// cout<<"\n"<<col<<"can place"<<i;
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board[i][col] = 1;
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/* recur to place rest of the queens */
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solveNQ(board, col + 1);
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board[i][col] = 0; // BACKTRACK
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}
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}
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}
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int main()
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{
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int board[N][N] = { {0, 0, 0, 0},
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{0, 0, 0, 0},
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{0, 0, 0, 0},
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{0, 0, 0, 0}
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};
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solveNQ(board, 0);
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return 0;
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}
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60
Strassen Matrix Multiplication.cpp
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60
Strassen Matrix Multiplication.cpp
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#include <iostream>
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using namespace std;
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Multiply(int A[][], int B[][], int n)
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{
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if (n==2)
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{
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int p1= (a[0][0] + a[1][1])*(b[0][0]+b[1][1]);
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int p2= (a[1][0]+a[1][1])*b[0][0];
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int p3= a[0][0]*(b[0][1]-b[1][1]);
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int p4= a[1][1]*(b[1][0]-b[0][0]);
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int p5= (a[0][0]+a[0][1])*b[1][1];
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int p6= (a[1][0]-a[0][0])*(b[0][0]+b[0][1]);
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int p7= (a[0][1]-a[1][1])*(b[1][0]+b[1][1]);
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int c[n][n];
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c[0][0]=p1+p4-p5+p7;
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c[0][1]=p3+p5;
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c[1][0]=p2+p4;
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c[1][1]=p1-p2+p3+p6;
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return c[][];
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}
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else
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{
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}
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}
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int main()
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{
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int p,q,r,s;
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cout<<"Enter the dimensions of Matrices";
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cin>>n;
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int A[n][n],;
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int B[n][n],;
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cout<<"Enter the elements of Matrix A";
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for (int i = 0; i < n; i++)
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{
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for (int j = 0; j <n ; j++)
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{
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cin>>A[i][j];
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}
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}
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cout<<"Enter the elements of Matrix B";
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for (int i = 0; i < n; i++)
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{
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for (int j = 0; j <n ; j++)
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{
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cin>>B[i][j];
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}
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}
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Multiply(A, B, n);
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return 0;
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}
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