fix : removed bad practice of using namespace td

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Ameya Chawla 2021-10-17 23:21:23 +05:30 committed by GitHub
parent 748ba48e9d
commit 2e8077fbb3
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@ -15,7 +15,6 @@
#include<complex>///For storing points and coefficents
#include <cassert>///For Assertions
# define pi 3.14159265358979323846
using namespace std;
/**
* @brief FastFourierTransform is a recursive function which returns list of complex numbers
@ -25,16 +24,16 @@ using namespace std;
* @returns y if n!=1
*/
complex<double>* FastFourierTransform(complex<double>*p,int n)
std::complex<double>* FastFourierTransform(std::complex<double>*p,int n)
{
if(n==1) return p; ///Base Case To return
complex<double> om=complex<double>(cos(2*pi/n),sin(2*pi/n)); ///Calculating value of omega
std::complex<double> om=std::complex<double>(cos(2*pi/n),sin(2*pi/n)); ///Calculating value of omega
complex<double> *pe= new complex<double>[n/2]; /// Coefficents of even power
std::complex<double> *pe= new std::complex<double>[n/2]; /// Coefficents of even power
complex<double> *po= new complex<double>[n/2]; ///Coefficents of odd power
std::complex<double> *po= new std::complex<double>[n/2]; ///Coefficents of odd power
int k1=0,k2=0;
for(int j=0;j<n;j++)
@ -48,11 +47,11 @@ complex<double>* FastFourierTransform(complex<double>*p,int n)
}
complex<double>*ye=FastFourierTransform(pe,n/2);///Recursive Call
std::complex<double>*ye=FastFourierTransform(pe,n/2);///Recursive Call
complex<double>*yo=FastFourierTransform(po,n/2);///Recursive Call
std::complex<double>*yo=FastFourierTransform(po,n/2);///Recursive Call
complex<double>*y=new complex<double>[n];///Final value representation list
std::complex<double>*y=new std::complex<double>[n];///Final value representation list
for(int i=0;i<n/2;i++)
@ -74,23 +73,23 @@ complex<double>* FastFourierTransform(complex<double>*p,int n)
static void test() {
/* descriptions of the following test */
complex<double> t1[2]={1,2};///Test case 1
std::complex<double> t1[2]={1,2};///Test case 1
complex<double> t2[4]={1,2,3,4};///Test case 2
std::complex<double> t2[4]={1,2,3,4};///Test case 2
int n1=sizeof(t1)/sizeof(complex<double>);
int n2=sizeof(t2)/sizeof(complex<double>);
int n1=sizeof(t1)/sizeof(std::complex<double>);
int n2=sizeof(t2)/sizeof(std::complex<double>);
complex<double> r1[2]={{3,0},{-1,0} };///True Answer for test case 1
std::complex<double> r1[2]={{3,0},{-1,0} };///True Answer for test case 1
complex<double> r2[4]={{10,0},{-2,-2},{-2,0},{-2,2} };///True Answer for test case 2
std::complex<double> r2[4]={{10,0},{-2,-2},{-2,0},{-2,2} };///True Answer for test case 2
complex<double> *o1=FastFourierTransform(t1,n1);
complex<double> *o2=FastFourierTransform(t2,n2);
std::complex<double> *o1=FastFourierTransform(t1,n1);
std::complex<double> *o2=FastFourierTransform(t2,n2);
for(int i=0;i<n1;i++)