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Longest Common Subsequence with subsequence printing
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//Longest common subsequence - Dynamic Programming
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#include <iostream>
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using namespace std;
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void Print(int trace[20][20], int m, int n, string a)
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{
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if (m==0 || n==0)
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{
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return;
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}
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if (trace[m][n]==1)
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{
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Print(trace, m-1, n-1, a);
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cout<<a[m-1];
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}
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else if(trace[m][n]==2)
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{
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Print(trace, m-1,n, a);
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}
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else if (trace[m][n]==3)
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{
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Print(trace, m,n-1, a);
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}
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}
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int lcs(string a, string b){
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int m = a.length(), n = b.length();
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int res[m+1][n+1];
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int trace[20][20];
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for (int i = 0; i < m+1; ++i)
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{
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for (int j = 0; j < n+1; ++j)
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{
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if(i==0||j==0)
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res[i][j] = 0;
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{
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res[i][j] = 0;
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trace[i][j]=0;
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}
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else if(a[i-1]==b[j-1])
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{
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res[i][j] = 1 + res[i-1][j-1];
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trace[i][j]=1; // 1 means trace the matrix in upper left diagonal direction.
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}
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else
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res[i][j] = max(res[i-1][j], res[i][j-1]);
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{
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if (res[i-1][j]>res[i][j-1])
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{
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res[i][j]=res[i-1][j];
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trace[i][j]=2; // 2 means trace the matrix in upwards direction.
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}
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else
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{
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res[i][j]=res[i][j-1];
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trace[i][j]=3; // means trace the matrix in left direction.
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}
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}
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}
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}
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Print(trace, m, n, a);
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return res[m][n];
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}
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int main()
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{
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string a,b;
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