feat: improve the Armstrong Number algorithm (#2480)

Co-authored-by: realstealthninja <68815218+realstealthninja@users.noreply.github.com>
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David Leal 2023-07-19 14:33:55 -06:00 committed by GitHub
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// Program to check whether a number is an armstrong number or not
#include <cmath>
#include <iostream>
using std::cin;
using std::cout;
/**
* @file
* @brief Checks whether a number is an [Armstrong
* Number](https://en.wikipedia.org/wiki/Narcissistic_number) or not.
*
* @details
* An Armstrong number is a number that is the sum of its own digits each raised
* to the power of the number of digits. For example: 153 is an Armstrong number
* since 153 = 1^3 + 5^3 + 3^3.
*
* A few examples of valid armstrong numbers:
* 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 153, 370, 371, 407, 1634, 8208, 9474, 54748,
* 92727, 93084.
*
* Armstrong numbers are also known as Narcissistic Numbers, as stated in
* Wikipedia.
*
* @author [Shivam Singhal](https://github.com/shivhek25)
* @author [David Leal](https://github.com/Panquesito7)
*/
int main() {
int n = 0, temp = 0, rem = 0, count = 0, sum = 0;
cout << "Enter a number: ";
cin >> n;
#include <cassert> /// for assert
#include <cmath> /// for std::pow
#include <iostream> /// for IO operations
temp = n;
/**
* @namespace
* @brief Dynamic Programming algorithms
*/
namespace dynamic_programming {
/* First Count the number of digits
in the given number */
/**
* @brief Checks if the given number is armstrong or not.
* @param number the number to check
* @returns false if the given number is NOT armstrong
* @returns true if the given number IS armstrong
*/
template <typename T>
bool is_armstrong(const T &number) {
int count = 0, temp = number, result = 0, rem = 0;
// Count the number of digits of the given number.
// For example: 153 would be 3 digits.
while (temp != 0) {
temp /= 10;
count++;
}
/* Calculation for checking of armstrongs number i.e.
in an n-digit number sum of the digits is raised to a power of n
is equal to the original number */
temp = n;
// Calculation for checking of armstrongs number i.e.
// in an n-digit number sum of the digits is raised to a power of `n` is
// equal to the original number.
temp = number;
while (temp != 0) {
rem = temp % 10;
sum += static_cast<int>(pow(rem, count));
result += static_cast<T>(std::pow(rem, count));
temp /= 10;
}
if (sum == n) {
cout << n << " is an armstrong number";
if (result == number) {
return true;
} else {
cout << n << " is not an armstrong number";
return false;
}
}
} // namespace dynamic_programming
/**
* @brief Self-test implementations
* @returns void
*/
static void tests() {
assert(dynamic_programming::is_armstrong(153) == true);
assert(dynamic_programming::is_armstrong(1) == true);
assert(dynamic_programming::is_armstrong(0) == true);
assert(dynamic_programming::is_armstrong(370) == true);
assert(dynamic_programming::is_armstrong(1634) == true);
assert(dynamic_programming::is_armstrong(580) == false);
assert(dynamic_programming::is_armstrong(15) == false);
assert(dynamic_programming::is_armstrong(1024) == false);
assert(dynamic_programming::is_armstrong(989) == false);
assert(dynamic_programming::is_armstrong(103) == false);
std::cout << "All tests have successfully passed!\n";
}
/**
* @brief Main function
* @returns 0 on exit
*/
int main() {
tests(); // run self-test implementations
return 0;
}