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clang-format and clang-tidy fixes for 405d21a5
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@ -4,10 +4,10 @@
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* (IFFT)](https://www.geeksforgeeks.org/python-inverse-fast-fourier-transformation/)
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* is an algorithm that computes the inverse fourier transform.
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* @details
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* This algorithm has an application in use case scenario where a user wants find coefficients of
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* a function in a short time by just using points generated by DFT.
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* Time complexity
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* this algorithm computes the IDFT in O(nlogn) time in comparison to traditional O(n^2).
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* This algorithm has an application in use case scenario where a user wants
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* find coefficients of a function in a short time by just using points
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* generated by DFT. Time complexity this algorithm computes the IDFT in
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* O(nlogn) time in comparison to traditional O(n^2).
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* @author [Ameya Chawla](https://github.com/ameyachawlaggsipu)
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*/
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@ -23,14 +23,15 @@
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*/
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namespace numerical_methods {
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/**
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* @brief InverseFastFourierTransform is a recursive function which returns list of
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* complex numbers
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* @brief InverseFastFourierTransform is a recursive function which returns list
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* of complex numbers
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* @param p List of Coefficents in form of complex numbers
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* @param n Count of elements in list p
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* @returns p if n==1
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* @returns y if n!=1
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*/
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std::complex<double> *InverseFastFourierTransform(std::complex<double> *p, uint8_t n) {
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std::complex<double> *InverseFastFourierTransform(std::complex<double> *p,
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uint8_t n) {
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if (n == 1) {
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return p; /// Base Case To return
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}
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@ -40,8 +41,8 @@ std::complex<double> *InverseFastFourierTransform(std::complex<double> *p, uint8
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std::complex<double> om = std::complex<double>(
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cos(2 * pi / n), sin(2 * pi / n)); /// Calculating value of omega
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om.real(om.real()/n); /// One change in comparison with DFT
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om.imag(om.imag()/n); /// One change in comparison with DFT
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om.real(om.real() / n); /// One change in comparison with DFT
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om.imag(om.imag() / n); /// One change in comparison with DFT
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auto *pe = new std::complex<double>[n / 2]; /// Coefficients of even power
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@ -52,8 +53,9 @@ std::complex<double> *InverseFastFourierTransform(std::complex<double> *p, uint8
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if (j % 2 == 0) {
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pe[k1++] = p[j]; /// Assigning values of even Coefficients
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} else
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} else {
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po[k2++] = p[j]; /// Assigning value of odd Coefficients
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}
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}
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std::complex<double> *ye =
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@ -76,11 +78,9 @@ std::complex<double> *InverseFastFourierTransform(std::complex<double> *p, uint8
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k2++;
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}
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if(n!=2){
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if (n != 2) {
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delete[] pe;
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delete[] po;
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}
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delete[] ye; /// Deleting dynamic array ye
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@ -118,16 +118,17 @@ static void test() {
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std::vector<std::complex<double>> r2 = {
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{1, 0}, {2, 0}, {3, 0}, {4, 0}}; /// True Answer for test case 2
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std::complex<double> *o1 = numerical_methods::InverseFastFourierTransform(t1, n1);
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std::complex<double> *o1 =
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numerical_methods::InverseFastFourierTransform(t1, n1);
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std::complex<double> *o2 = numerical_methods::InverseFastFourierTransform(t2, n2);
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std::complex<double> *o2 =
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numerical_methods::InverseFastFourierTransform(t2, n2);
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for (uint8_t i = 0; i < n1; i++) {
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assert((r1[i].real() - o1[i].real() < 0.000000000001) &&
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(r1[i].imag() - o1[i].imag() <
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0.000000000001)); /// Comparing for both real and imaginary
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/// values for test case 1
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}
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for (uint8_t i = 0; i < n2; i++) {
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@ -135,10 +136,8 @@ static void test() {
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(r2[i].imag() - o2[i].imag() <
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0.000000000001)); /// Comparing for both real and imaginary
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/// values for test case 2
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}
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delete[] t1;
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delete[] t2;
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delete[] o1;
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