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AkVaya 2020-08-14 10:04:21 +05:30
parent d87a6685f6
commit ab26183183
1 changed files with 14 additions and 10 deletions
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graph/is_graph_bipartite.cpp
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@ -1,8 +1,7 @@
/** /**
* @file is_graph_bipartite * @file is_graph_bipartite
* *
* @brief Algorithm to check whether a graph is bipartite * @brief Algorithm to check whether a graph is [bipartite](https://en.wikipedia.org/wiki/Bipartite_graph)
* (https://en.wikipedia.org/wiki/Bipartite_graph)
* *
* @details * @details
* A graph is a collection of nodes also called vertices and these vertices * A graph is a collection of nodes also called vertices and these vertices
@ -25,7 +24,6 @@
* \ / * \ /
* 3 * 3
* *
*
* @author [Akshat Vaya](https://github.com/AkVaya) * @author [Akshat Vaya](https://github.com/AkVaya)
* *
*/ */
@ -74,10 +72,16 @@ void graph::addEdge(int u, int v) {
* @brief function that checks whether the graph is bipartite or not * @brief function that checks whether the graph is bipartite or not
* the function returns true if the graph is a bipartite graph * the function returns true if the graph is a bipartite graph
* the function returns false if the graph is not a bipartite graph * the function returns false if the graph is not a bipartite graph
*
* @details
* Here, side refers to the two disjoint subsets of the bipartite graph.
* Initially, the values of side are set to -1 which is an unassigned state. A for loop is run for every vertex of the graph.
* If the current edge has no side assigned to it, then a Breadth First Search operation is performed.
* If two neighbours have the same side then the graph will not be bipartite and the value of check becomes false.
* If and only if each pair of neighbours have different sides, the value of check will be true and hence the graph bipartite.
*
*/ */
bool graph::is_bipartite(){ bool graph::is_bipartite(){
n = adj.size();
side.resize(n,-1);
bool check = true; bool check = true;
std::queue<int> q; std::queue<int> q;
for (int current_edge = 0; current_edge < n; ++current_edge) for (int current_edge = 0; current_edge < n; ++current_edge)