mirror of
https://hub.njuu.cf/TheAlgorithms/C-Plus-Plus.git
synced 2023-10-11 13:05:55 +08:00
Merge pull request #773 from coderanant/master
feat: add algo to find no of connected components with Union Find Structure
This commit is contained in:
commit
f956bd6ba4
55
graph/connected_components_with_dsu.cpp
Normal file
55
graph/connected_components_with_dsu.cpp
Normal file
@ -0,0 +1,55 @@
|
||||
#include <iostream>
|
||||
#include <vector>
|
||||
#include <set>
|
||||
|
||||
int N; // denotes number of nodes;
|
||||
std::vector<int> parent;
|
||||
std::vector<int> siz;
|
||||
void make_set() { // function the initialize every node as it's own parent
|
||||
for (int i = 1; i <= N; i++) {
|
||||
parent[i] = i;
|
||||
siz[i] = 1;
|
||||
}
|
||||
}
|
||||
// To find the component where following node belongs to
|
||||
int find_set(int v) {
|
||||
if (v == parent[v])
|
||||
return v;
|
||||
return parent[v] = find_set(parent[v]);
|
||||
}
|
||||
|
||||
void union_sets(int a, int b) { // To join 2 components to belong to one
|
||||
a = find_set(a);
|
||||
b = find_set(b);
|
||||
if (a != b) {
|
||||
if (siz[a] < siz[b])
|
||||
std::swap(a, b);
|
||||
parent[b] = a;
|
||||
siz[a] += siz[b];
|
||||
}
|
||||
}
|
||||
|
||||
int no_of_connected_components() { // To find total no of connected components
|
||||
std::set<int> temp; // temp set to count number of connected components
|
||||
for (int i = 1; i <= N; i++)
|
||||
temp.insert(find_set(i));
|
||||
return temp.size();
|
||||
}
|
||||
|
||||
// All critical/corner cases have been taken care of.
|
||||
// Input your required values: (not hardcoded)
|
||||
int main() {
|
||||
std::cin >> N;
|
||||
parent.resize(N + 1);
|
||||
siz.resize(N + 1);
|
||||
make_set();
|
||||
int edges;
|
||||
std::cin >> edges; // no of edges in the graph
|
||||
while (edges--) {
|
||||
int node_a, node_b;
|
||||
std::cin >> node_a >> node_b;
|
||||
union_sets(node_a, node_b);
|
||||
}
|
||||
std::cout << no_of_connected_components() << std::endl;
|
||||
return 0;
|
||||
}
|
Loading…
Reference in New Issue
Block a user