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https://hub.njuu.cf/TheAlgorithms/C-Plus-Plus.git
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159 lines
5.8 KiB
C++
159 lines
5.8 KiB
C++
#include <iostream>
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using namespace std;
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//node defined
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class node
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{
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public:
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int data;
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node *link;
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node(int d)
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{
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data = d;
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link = NULL;
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}
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};
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//printing the linked list
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void print(node *head)
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{
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node *current = head;
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while (current != NULL)
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{
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cout << current->data << " ";
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current = current->link;
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}
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cout << endl;
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}
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//creating the linked list with 'n' nodes
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node *createlist(int n)
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{
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node *head = NULL;
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node *t = NULL;
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for (int i = 0; i < n; i++)
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{
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node *temp = NULL;
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int num;
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cin >> num;
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temp = new node(num);
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if (head == NULL)
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{
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head = temp;
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t = temp;
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continue;
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}
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if (t->link == NULL)
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t->link = temp;
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t = temp;
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}
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return head;
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}
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//performing selection sort on the linked list in an iterative manner
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void my_selection_sort_linked_list(node *&head)
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{
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node *min = head; //throughout the algorithm 'min' is used to denote the node with min value out of all the nodes left for scanning
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//while scanning if we find a node 'X' with value lesser than min,
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//then we update the pointers in such a way that 'X' becomes the predecessor of 'min'
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node *current = min->link; // 'current' refers to the current node we are scanning
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node *previous = min; //'previous' refers to the node that is previous to the current node
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node *temp = NULL; // 'temp' in this algo is used to point to the last node of the sorted part of the linked list.
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//eg. If at any time instance the state of the linked list is suppose 1->2->5->3->8->NULL
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//then, we see that "1->2" is the sorted part of the LL, and therefore temp will be pointing to the last node of the sorted part,i.e,'2'
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//We keep on arranging the Linked list in such a way that after each iteration the node with 'min' value is placed at its correct position.
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//Eg. Let suppose initially we have 5->4->1->3->2->NULL
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//After 1st iteration : 1->4->5->3->2->NULL and so on
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while (min->link != NULL) //so that all the nodes are scanned or until there exists a node
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{
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//pick the first node from the unsorted part and assume that it is the minimum and then start scanning from the next node
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while (current != NULL) //suppose you choose the min node to be X, then scan starts from the (X+1)th node until its NULL. current = (X+1)th node and min = X
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{
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if (current->data < min->data) //if the current node is smaller than the presumed node 'min'
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{
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if (temp == NULL) //temp stays null for the first iteration, therefore it symbolizes that we are scanning for the first time
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{
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if (previous == min) //if the 'previous' is pointing to the 'min' node
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{
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//Update the pointers
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head = current; //update the head pointer with the current node
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min->link = current->link;
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current->link = previous;
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min = current;
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current = previous->link;
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}
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else //if the 'previous' is not pointing to the 'min' node
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{
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//Update the pointers
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head = current; //update the head pointer with the current node
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previous->link = current->link;
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current->link = min;
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min = current;
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current = previous->link;
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}
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}
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else //if 'temp' is not NULL, i.e., its not the 1st iteration
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{
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temp->link = current;
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previous->link = current->link;
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current->link = min;
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min = current;
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current = previous->link;
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}
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}
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else //if the current node is greater than min, just move the previous and the current pointer a step further
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{
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previous = previous->link;
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current = current->link;
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}
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}
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//update the pointers. Set 'temp' to the last node in the sorted part. Make 'min' move a step further so that 'min' points to the 1st node of the unsorted part
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//start the iteration again
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temp = min;
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min = min->link;
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previous = min;
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current = min->link;
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}
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}
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// Test cases:
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// enter the no. of nodes : 5
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// 8 9 3 1 4
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// original list is : 8 9 3 1 4
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// sorted list is : 1 3 4 8 9
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// enter the no. of nodes : 3
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// -1 -2 -3
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// original list is : -1 -2 -3
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// sorted list is : -3 -2 -1
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// enter the no. of nodes : 8
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// 8 7 6 5 4 3 2 1
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// original list is : 8 7 6 5 4 3 2 1
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// sorted list is : 1 2 3 4 5 6 7 8
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// enter the no. of nodes : 6
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// 5 3 4 1 -2 -4
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// original list is : 5 3 4 1 -2 -4
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// sorted list is : -4 -2 1 3 4 5
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int main()
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{
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node *head = NULL;
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int n;
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cout << "enter the no. of nodes : "; //taking input from user about the number of nodes in linked list
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cin >> n;
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if (n == 0)
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return 0;
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head = createlist(n); //creating the list
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cout << "original list is : ";
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print(head); //printing the original linked list
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my_selection_sort_linked_list(head); //applying selection sort
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cout << "sorted list is : ";
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print(head); //printing the sorted linked list
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return 0;
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} |