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67 lines
1.5 KiB
C++
67 lines
1.5 KiB
C++
/**
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* \file
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* \brief Solve the equation \f$f(x)=0\f$ using [Newton-Raphson
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* method](https://en.wikipedia.org/wiki/Newton%27s_method) for both real and
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* complex solutions
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*
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* The \f$(i+1)^\text{th}\f$ approximation is given by:
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* \f[
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* x_{i+1} = x_i - \frac{f(x_i)}{f'(x_i)}
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* \f]
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*
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* \author [Krishna Vedala](https://github.com/kvedala)
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* \see bisection_method.cpp, false_position.cpp
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*/
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#include <cmath>
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#include <ctime>
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#include <iostream>
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#include <limits>
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#define EPSILON 1e-10 ///< system accuracy limit
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#define MAX_ITERATIONS INT16_MAX ///< Maximum number of iterations to check
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/** define \f$f(x)\f$ to find root for.
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* Currently defined as:
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* \f[
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* f(x) = x^3 - 4x - 9
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* \f]
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*/
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static double eq(double i) {
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return (std::pow(i, 3) - (4 * i) - 9); // original equation
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}
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/** define the derivative function \f$f'(x)\f$
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* For the current problem, it is:
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* \f[
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* f'(x) = 3x^2 - 4
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* \f]
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*/
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static double eq_der(double i) {
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return ((3 * std::pow(i, 2)) - 4); // derivative of equation
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}
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/** Main function */
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int main() {
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std::srand(std::time(nullptr)); // initialize randomizer
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double z, c = std::rand() % 100, m, n;
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int i;
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std::cout << "\nInitial approximation: " << c;
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// start iterations
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for (i = 0; i < MAX_ITERATIONS; i++) {
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m = eq(c);
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n = eq_der(c);
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z = c - (m / n);
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c = z;
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if (std::abs(m) < EPSILON) // stoping criteria
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break;
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}
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std::cout << "\n\nRoot: " << z << "\t\tSteps: " << i << std::endl;
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return 0;
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}
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