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70868f2b5e
* feat: add manacher algorithm in strings/ * fix: directory.md format * fix: add test cases, fix clang-tidy warning, implement requested changes * fix: update comments * fix: update int to uint64_t, add suggested changes * fix: update description
175 lines
6.7 KiB
C++
175 lines
6.7 KiB
C++
/**
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* @file
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* @brief Implementation of [Manacher's
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* Algorithm](https://en.wikipedia.org/wiki/Longest_palindromic_substring)
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* @details
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* Manacher's Algorithm is used to find the longest palindromic substring within
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* a string in O(n) time. It exploits the property of a palindrome that its
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* first half is symmetric to the last half, and thus if the first half is a
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* palindrome, then last half is also a palindrome.
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* @author [Riti Kumari](https://github.com/riti2409)
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*/
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#include <cassert> /// for assert
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#include <iostream> /// for IO operations
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#include <vector> /// for std::vector STL
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#ifdef _MSC_VER
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#include <string> /// for string (required for MS Visual C++)
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#else
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#include <cstring> /// for string
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#endif
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/**
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* @namespace strings
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* @brief Algorithms with strings
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*/
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namespace strings {
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/**
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* @namespace manacher
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* @brief Functions for [Manacher's
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* Algorithm](https://en.wikipedia.org/wiki/Longest_palindromic_substring)
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* implementation
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*/
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namespace manacher {
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/**
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* @brief A function that implements Manacher's algorithm
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* @param prototype is the string where algorithm finds a palindromic substring.
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* This string can contain any character except `@` `#` `&`
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* @returns the largest palindromic substring
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*/
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std::string manacher(const std::string &prototype) {
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if (prototype.size() > 0) {
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// stuffing characters between the input string to handle cases with
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// even length palindrome
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std::string stuffed_string = "";
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for (auto str : prototype) {
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stuffed_string += str;
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stuffed_string += "#";
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}
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stuffed_string = "@#" + stuffed_string + "&";
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std::vector<uint64_t> palindrome_max_half_length(
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stuffed_string.size(),
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0); // this array will consist of largest possible half length of
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// palindrome centered at index (say i with respect to the
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// stuffed string). This value will be lower bound of half
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// length since single character is a palindrome in itself.
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uint64_t bigger_center =
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0; // this is the index of the center of palindromic
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// substring which would be considered as the larger
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// palindrome, having symmetric halves
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uint64_t right = 0; // this is the maximum length of the palindrome
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// from 'bigger_center' to the rightmost end
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// i is considered as center lying within one half of the palindrone
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// which is centered at 'bigger_center'
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for (uint64_t i = 1; i < stuffed_string.size() - 1; i++) {
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if (i < right) { // when i is before right end, considering
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// 'bigger_center' as center of palindrome
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uint64_t opposite_to_i =
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2 * bigger_center -
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i; // this is the opposite end of string, if
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// centered at center, and having one end as i
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// finding the minimum possible half length among
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// the palindrome on having center at opposite end,
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// and the string between i and right end,
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// considering 'bigger_center' as center of palindrome
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palindrome_max_half_length[i] = std::min(
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palindrome_max_half_length[opposite_to_i], right - i);
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}
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// expanding the palindrome across the maximum stored length in the
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// array, centered at i
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while (stuffed_string[i + (palindrome_max_half_length[i] + 1)] ==
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stuffed_string[i - (palindrome_max_half_length[i] + 1)]) {
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palindrome_max_half_length[i]++;
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}
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// if palindrome centered at i exceeds the rightmost end of
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// palindrome centered at 'bigger_center', then i will be made the
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// 'bigger_center' and right value will also be updated with respect
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// to center i
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if (i + palindrome_max_half_length[i] > right) {
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bigger_center = i;
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right = i + palindrome_max_half_length[i];
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}
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}
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// now extracting the first largest palindrome
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uint64_t half_length = 0; // half length of the largest palindrome
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uint64_t center_index = 0; // index of center of the largest palindrome
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for (uint64_t i = 1; i < stuffed_string.size() - 1; i++) {
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if (palindrome_max_half_length[i] > half_length) {
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half_length = palindrome_max_half_length[i];
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center_index = i;
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}
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}
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std::string palindromic_substring =
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""; // contains the resulting largest palindrome
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if (half_length > 0) {
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// extra information: when '#' is the center, then palindromic
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// substring will have even length, else palindromic substring will
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// have odd length
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uint64_t start =
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center_index - half_length +
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1; // index of first character of palindromic substring
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uint64_t end =
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center_index + half_length -
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1; // index of last character of palindromic substring
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for (uint64_t index = start; index <= end; index += 2) {
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palindromic_substring += stuffed_string[index];
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}
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} else {
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// if length = 0, then there does not exist any palindrome of length
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// > 1 so we can assign any character of length 1 from string as the
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// palindromic substring
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palindromic_substring = prototype[0];
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}
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return palindromic_substring;
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} else {
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// handling case when string is empty
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return "";
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}
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}
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} // namespace manacher
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} // namespace strings
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/**
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* @brief Self-test implementations
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* @returns void
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*/
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static void test() {
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assert(strings::manacher::manacher("") == "");
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assert(strings::manacher::manacher("abababc") == "ababa");
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assert(strings::manacher::manacher("cbaabd") == "baab");
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assert(strings::manacher::manacher("DedzefDeD") == "DeD");
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assert(strings::manacher::manacher("XZYYXXYZXX") == "YXXY");
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assert(strings::manacher::manacher("1sm222m10abc") == "m222m");
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assert(strings::manacher::manacher("798989591") == "98989");
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assert(strings::manacher::manacher("xacdedcax") == "xacdedcax");
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assert(strings::manacher::manacher("xaccax") == "xaccax");
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assert(strings::manacher::manacher("a") == "a");
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assert(strings::manacher::manacher("xy") == "x");
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assert(strings::manacher::manacher("abced") == "a");
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std::cout << "All tests have passed!" << std::endl;
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}
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/**
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* @brief Main function
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* @returns 0 on exit
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*/
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int main() {
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test(); // run self-test implementations
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return 0;
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}
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