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19 lines
383 B
C
19 lines
383 B
C
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/*
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If we list all the natural numbers below 10 that are multiples of 3 or 5,
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we get 3, 5, 6 and 9. The sum of these multiples is 23.
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Find the sum of all the multiples of 3 or 5 below 1000.
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*/
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#include <stdio.h>
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int main() {
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int n = 0;
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int sum = 0;
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scanf("%d", &n);
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for (int a = 0; a < n; a++) {
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if ((a % 3 == 0) || (a % 5 == 0)) {
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sum += a;
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}
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}
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printf("%d\n", sum);
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}
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