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feat: add Redundant Connection (#1181)
Co-authored-by: David Leal <halfpacho@gmail.com>
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| 647 | [Palindromic Substring](https://leetcode.com/problems/palindromic-substrings/) | [C](./src/647.c) | Medium |
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| 647 | [Palindromic Substring](https://leetcode.com/problems/palindromic-substrings/) | [C](./src/647.c) | Medium |
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| 669 | [Trim a Binary Search Tree](https://leetcode.com/problems/trim-a-binary-search-tree/) | [C](./src/669.c) | Medium |
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| 669 | [Trim a Binary Search Tree](https://leetcode.com/problems/trim-a-binary-search-tree/) | [C](./src/669.c) | Medium |
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| 674 | [Longest Continuous Increasing Subsequence](https://leetcode.com/problems/longest-continuous-increasing-subsequence/) | [C](./src/674.c) | Easy |
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| 674 | [Longest Continuous Increasing Subsequence](https://leetcode.com/problems/longest-continuous-increasing-subsequence/) | [C](./src/674.c) | Easy |
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| 684 | [Redundant Connection](https://leetcode.com/problems/redundant-connection/description/) | [C](./src/684.c) | Medium |
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| 700 | [Search in a Binary Search Tree](https://leetcode.com/problems/search-in-a-binary-search-tree/) | [C](./src/700.c) | Easy |
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| 700 | [Search in a Binary Search Tree](https://leetcode.com/problems/search-in-a-binary-search-tree/) | [C](./src/700.c) | Easy |
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| 701 | [Insert into a Binary Search Tree](https://leetcode.com/problems/insert-into-a-binary-search-tree/) | [C](./src/701.c) | Medium |
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| 701 | [Insert into a Binary Search Tree](https://leetcode.com/problems/insert-into-a-binary-search-tree/) | [C](./src/701.c) | Medium |
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| 704 | [Binary Search](https://leetcode.com/problems/binary-search/) | [C](./src/704.c) | Easy |
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| 704 | [Binary Search](https://leetcode.com/problems/binary-search/) | [C](./src/704.c) | Easy |
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49
leetcode/src/684.c
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49
leetcode/src/684.c
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/**
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* Note: The returned array must be malloced, assume caller calls free().
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*/
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int find(int* sets, int index){
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while (sets[index] != index){
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index = sets[index];
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}
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return index;
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}
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void unionSet(int* sets, int i1, int i2){
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int i1Parent = find(sets, i1);
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int i2Parent = find(sets, i2);
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sets[i1Parent] = i2Parent;
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}
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// Union find
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// Runtime: O(n)
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// Space: O(n)
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int* findRedundantConnection(int** edges, int edgesSize, int* edgesColSize, int* returnSize){
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int setsSize = edgesSize + 1;
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int* sets = malloc(setsSize * sizeof(int));
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for (int i = 0; i < setsSize; i++){
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sets[i] = i;
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}
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int* result = malloc(2 * sizeof(int));
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*returnSize = 2;
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for (int i = 0; i < edgesSize; i++){
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int* edge = edges[i];
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int i0Parent = find(sets, edge[0]);
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int i1Parent = find(sets, edge[1]);
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if (i0Parent == i1Parent){
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result[0] = edge[0];
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result[1] = edge[1];
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continue;
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}
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unionSet(sets, i0Parent, i1Parent);
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}
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free(sets);
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return result;
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}
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