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Add more solution for leetcode
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commit
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@ -1,19 +0,0 @@
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// for strlen( )
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#include<string.h>
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int numJewelsInStones(char * j, char * s){
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// as strlen is O(n), store it once rather than using it in for loop
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int cnt[500],lens=strlen(s),lenj=strlen(j),sol=0;
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memset(cnt,0,sizeof(cnt));
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// lookup to know which character occurs in j
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for(int i=0;i<lenj;i++)
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cnt[j[i]]++;
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// count the characters in s
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for(int i=0;i<lens;i++)
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sol+=cnt[s[i]];
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return sol;
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}
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@ -6,10 +6,19 @@ LeetCode
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| # | Title | Solution | Difficulty |
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|---| ----- | -------- | ---------- |
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|3|[Longest Substring Without Repeating Characters](https://leetcode.com/problems/longest-substring-without-repeating-characters/) | [C](./src/3.c)|Medium|
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|20|[Valid Parentheses](https://leetcode.com/problems/valid-parentheses/) | [C](./src/20.c)|Easy|
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|26|[Remove Duplicates from Sorted Array](https://leetcode.com/problems/remove-duplicates-from-sorted-array/) | [C](./src/26.c)|Easy|
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|35|[Search Insert Position](https://leetcode.com/problems/search-insert-position/) | [C](./src/35.c)|Easy|
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|108|[Convert Sorted Array to Binary Search Tree](https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/) | [C](./src/108.c)|Easy|
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|125|[Valid Palindrome](https://leetcode.com/problems/valid-palindrome/) | [C](./src/125.c)|Easy|
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|136|[Single Number](https://leetcode.com/problems/single-number/) | [C](./src/136.c)|Easy|
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|141|[Linked List Cycle](https://leetcode.com/problems/linked-list-cycle/) | [C](./src/141.c)|Easy|
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|169|[Majority Element](https://leetcode.com/problems/majority-element/) | [C](./src/169.c)|Easy|
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|215|[Kth Largest Element in an Array](https://leetcode.com/problems/kth-largest-element-in-an-array/) | [C](./src/215.c)|Medium|
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|217|[Contains Duplicate](https://leetcode.com/problems/contains-duplicate/) | [C](./src/217.c)|Easy|
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|268|[Missing Number](https://leetcode.com/problems/missing-number/) | [C](./src/268.c)|Easy|
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|287|[Find the Duplicate Number](https://leetcode.com/problems/find-the-duplicate-number/) | [C](./src/287.c)|Medium|
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|344|[Reverse String](https://leetcode.com/problems/reverse-string/) | [C](./src/344.c)|Easy|
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|387|[First Unique Character in a String](https://leetcode.com/problems/first-unique-character-in-a-string/) | [C](./src/387.c)|Easy|
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|442|[Find All Duplicates in an Array](https://leetcode.com/problems/find-all-duplicates-in-an-array/) | [C](./src/442.c)|Medium|
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14
leetcode/src/1.c
Normal file
14
leetcode/src/1.c
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@ -0,0 +1,14 @@
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int* twoSum(int* nums, int numsSize, int target, int* returnSize){
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int i, j;
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int *ret = calloc(2, sizeof(int));
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for (i = 0; i < numsSize; i++) {
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int key = target - nums[i];
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for (j = i + 1; j < numsSize; j++)
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if (nums[j] == key) {
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ret[0] = i;
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ret[1] = j;
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}
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}
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*returnSize = 2;
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return ret;
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}
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29
leetcode/src/108.c
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29
leetcode/src/108.c
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@ -0,0 +1,29 @@
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/**
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* Definition for a binary tree node.
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* struct TreeNode {
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* int val;
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* struct TreeNode *left;
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* struct TreeNode *right;
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* };
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*/
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struct TreeNode* convertBST(int *nums, int left, int right) {
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if (left > right)
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return NULL;
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else {
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int mid = (right + left) / 2;
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struct TreeNode *new_val = malloc(sizeof(struct TreeNode));
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new_val->val = nums[mid];
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new_val->left = convertBST(nums, left, mid - 1);
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new_val->right = convertBST(nums, mid + 1, right);
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return new_val;
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}
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}
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struct TreeNode* sortedArrayToBST(int* nums, int numsSize){
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if(numsSize == 0)
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return NULL;
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else
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return convertBST(nums, 0, numsSize -1);
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}
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6
leetcode/src/136.c
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6
leetcode/src/136.c
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@ -0,0 +1,6 @@
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int singleNumber(int* nums, int numsSize){
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int i, result = 0;
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for(i = 0; i < numsSize; i++)
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result = result ^ nums[i];
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return result;
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}
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16
leetcode/src/141.c
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16
leetcode/src/141.c
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/**
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* Definition for singly-linked list.
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* struct ListNode {
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* int val;
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* struct ListNode *next;
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* };
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*/
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bool hasCycle(struct ListNode *head) {
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struct ListNode *fast=head, *slow=head;
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while( slow && fast && fast->next ){
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fast=fast->next->next;
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slow=slow->next;
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if(fast==slow) return true;
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}
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return false;
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}
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16
leetcode/src/169.c
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16
leetcode/src/169.c
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/* Boyer-Moore Majority Vote Algorithm
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* http://www.cs.utexas.edu/~moore/best-ideas/mjrty/ */
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int majorityElement(int* nums, int numsSize){
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int count = 1;
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int majorNum = nums[0];
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for (int i = 1; i < numsSize; i++) {
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if(count == 0) {
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majorNum = nums[i];
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count++;
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} else if (majorNum == nums[i])
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count++;
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else
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count--;
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}
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return majorNum;
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}
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29
leetcode/src/20.c
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29
leetcode/src/20.c
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bool isValid(char * s){
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int i, k = 0, len = strlen(s);
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char *store = calloc(len, sizeof(char));
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for( i = 0; s[i] != '\0'; i++) {
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switch(s[i]) {
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case '(':
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case '{':
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case '[':
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store[k++] = s[i];
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break;
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case ')':
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if(k < 1 || store[--k] != '(')
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goto out;
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break;
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case '}':
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if(k < 1 || store[--k] != '{')
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goto out;
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break;
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case ']':
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if(k < 1 || store[--k] != '[')
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goto out;
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break;
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}
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}
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out:
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free(store);
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return s[i] == '\0' && k == 0;
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}
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8
leetcode/src/215.c
Normal file
8
leetcode/src/215.c
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int *cmpval (const void *a, const void *b) {
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return *(int *)b - *(int *)a;
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}
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int findKthLargest(int* nums, int numsSize, int k){
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qsort(nums, numsSize, sizeof(int), cmpval);
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return nums[k-1];
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}
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8
leetcode/src/268.c
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8
leetcode/src/268.c
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int missingNumber(int* nums, int numsSize){
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int i, actual_sum = 0, sum = 0;
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for(i = 0; i < numsSize; i++) {
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sum = sum + nums[i];
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actual_sum = actual_sum + i;
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}
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return actual_sum + numsSize - sum;
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}
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13
leetcode/src/287.c
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13
leetcode/src/287.c
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int cmpval(const void *a, const void *b) {
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return *(int *)a - *(int *)b;
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}
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int findDuplicate(int* nums, int numsSize){
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int i;
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qsort(nums, numsSize, sizeof(int), cmpval);
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for(i = 0; i < numsSize - 1; i++) {
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if(nums[i] == nums[i+1])
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return nums[i];
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}
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return nums[i];
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}
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55
leetcode/src/3.c
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55
leetcode/src/3.c
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@ -0,0 +1,55 @@
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int lengthOfLongestSubstring(char* str) {
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int n = strlen(str);
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if(!n) return 0;
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int L_len = 1; // lenght of longest substring
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int C_len = 1; // lenght of current substring
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int P_ind, i; // P_ind for previous index
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int visited[256]; // visited will keep track of visiting char for the last instance.
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// since there are 256 ASCII char, its size is limited to that value.
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memset(visited, -1, sizeof(int) * 256);
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visited[str[0]] = 0; // the index of that char will tell us that when it was visited.
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for (i = 1; i < n; i++)
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{
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P_ind = visited[str[i]];
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if (P_ind == -1 || i - C_len > P_ind)
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C_len++; // if the current char was not visited earlier, or it is not the part of current substring
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else
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{ // otherwise, we need to change the current/longest substring length
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if (C_len > L_len) L_len = C_len;
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C_len = i - P_ind;
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}
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visited[str[i]] = i;
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}
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if (C_len > L_len) L_len = C_len;
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return L_len;
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}
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/* Brute force */
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int lengthOfLongestSubstring(char * s){
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int cur_max = 0, max = 0;
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int counter[255];
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int end = 0;
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memset(counter, 0, sizeof(int) *255);
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while (end < strlen(s)) {
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if (counter[s[end]] == 0) {
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counter[s[end]]++;
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end++;
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cur_max++;
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} else {
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char c = s[end];
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memset(counter, 0, 255 * sizeof(int));
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if (cur_max >= max)
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max = cur_max;
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cur_max = 0;
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while(s[end - 1] != c)
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end--;
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}
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}
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if (cur_max >= max)
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max = cur_max;
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return max;
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}
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