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Refactoring the syntax using list comprehension (#7749)

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* Refactoring the syntax using list comprehension

* Update detecting_english_programmatically.py

* Update detecting_english_programmatically.py

Co-authored-by: Christian Clauss <cclauss@me.com>
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SwayamSahu 2022-10-28 02:32:15 +05:30 committed by GitHub
parent 61eedc16c3
commit de3271ec80
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1 changed files with 4 additions and 16 deletions
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20
strings/detecting_english_programmatically.py
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@ -1,7 +1,7 @@
import os import os
from string import ascii_letters
UPPERLETTERS = "ABCDEFGHIJKLMNOPQRSTUVWXYZ" LETTERS_AND_SPACE = ascii_letters + " \t\n"
LETTERS_AND_SPACE = UPPERLETTERS + UPPERLETTERS.lower() + " \t\n"
def load_dictionary() -> dict[str, None]: def load_dictionary() -> dict[str, None]:
@ -20,24 +20,12 @@ def get_english_count(message: str) -> float:
message = message.upper() message = message.upper()
message = remove_non_letters(message) message = remove_non_letters(message)
possible_words = message.split() possible_words = message.split()
matches = len([word for word in possible_words if word in ENGLISH_WORDS])
if possible_words == []:
return 0.0
matches = 0
for word in possible_words:
if word in ENGLISH_WORDS:
matches += 1
return float(matches) / len(possible_words) return float(matches) / len(possible_words)
def remove_non_letters(message: str) -> str: def remove_non_letters(message: str) -> str:
letters_only = [] return "".join(symbol for symbol in message if symbol in LETTERS_AND_SPACE)
for symbol in message:
if symbol in LETTERS_AND_SPACE:
letters_only.append(symbol)
return "".join(letters_only)
def is_english( def is_english(