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# Time Complexity of Solution:
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# Best Case O(n); Average Case O(n); Worst Case O(n)
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from __future__ import print_function
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from insertion_sort import insertion_sort
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import math
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DEFAULT_BUCKET_SIZE=5
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def bucket_sort(my_list,bucket_size=DEFAULT_BUCKET_SIZE):
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if(my_list==0):
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print("you don't have any elements in array!")
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DEFAULT_BUCKET_SIZE = 5
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def bucketSort(myList, bucketSize=DEFAULT_BUCKET_SIZE):
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if(len(myList) == 0):
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print('You don\'t have any elements in array!')
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min_value=min(my_list)
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max_value=max(my_list)
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minValue = myList[0]
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maxValue = myList[0]
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# For finding minimum and maximum values
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for i in range(0, len(myList)):
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if myList[i] < minValue:
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minValue = myList[i]
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elif myList[i] > maxValue:
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maxValue = myList[i]
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# Initialize buckets
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bucketCount = math.floor((maxValue - minValue) / bucketSize) + 1
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buckets = []
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for i in range(0, bucketCount):
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bucket_count=(max_value-min_value)//bucket_size+1
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buckets=[]
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for i in range(bucket_count):
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buckets.append([])
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for i in range(len(my_list)):
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buckets[(my_list[i]-min_value)//bucket_size].append(my_list[i])
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# For putting values in buckets
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for i in range(0, len(myList)):
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buckets[math.floor((myList[i] - minValue) / bucketSize)].append(myList[i])
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# Sort buckets and place back into input array
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sortedArray = []
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for i in range(0, len(buckets)):
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insertion_sort(buckets[i])
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for j in range(0, len(buckets[i])):
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sortedArray.append(buckets[i][j])
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sorted_array=[]
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for i in range(len(buckets)):
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buckets[i].sort()
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for j in range(len(buckets[i])):
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sorted_array.append(buckets[i][j])
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return sorted_array
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return sortedArray
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if __name__ == '__main__':
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sortedArray = bucketSort([12, 23, 4, 5, 3, 2, 12, 81, 56, 95])
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print(sortedArray)
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#test
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#besd on python 3.7.3
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user_input =input('Enter numbers separated by a comma:').strip()
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unsorted =[int(item) for item in user_input.split(',')]
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print(bucket_sort(unsorted))
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